72x^2+140x=0

Solution for 72x^2+140x=0 equation:

72x^2+140x=0

a = 72; b = 140; c = 0;
Δ = b2-4ac
Δ = 1402-4·72·0
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-140}{2*72}=\frac{-280}{144}
=-1+17/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+140}{2*72}=\frac{0}{144}
=0
$